Find the rate at which the function f(x)=x^4-2x^3+3x^2+x+5change … - Vidyadip

Question

Find the rate at which the function $\text{f}(\text{x})=\text{x}^4-\text{2x}^3+\text{3x}^2+\text{x}+5$change with respect to $\text{x}.$

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Answer

We have,$\text{f}(\text{x})=\text{x}^4-\text{2x}^3+\text{3x}^2+\text{x}+5$
Differentiate with respect to $\text{x}$
$\frac{\text{d}}{\text{dx}}\text{f}(\text{x})=\frac{\text{d}}{\text{dx}}(\text{x}^4-\text{2x}^3+\text{3x}^2+\text{x}+5)$
$=\text{4x}^3-\text{6x}^2+\text{6x}+1$

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