Question
Find the remainder when$ 2x^3 – 3x^2 + 4x + 7$ is divided by $x – 2$
✓
Answer
$f(x) = 2x^3 – 3x^2 + 4x + 7$
Let $x – 2 = 0,$
then $x = 2$
Substituting value of x in $f(x)$
$f(2) = 2 (2)^3 – 3 (2)^2 + 4 (2) + 7$
$= 2 \times 8 – 3 \times 4 + 4 \times 2 + 7$
$= 16 – 12 + 8 + 7$
$= 19$
Remainder $= 19$
Let $x – 2 = 0,$
then $x = 2$
Substituting value of x in $f(x)$
$f(2) = 2 (2)^3 – 3 (2)^2 + 4 (2) + 7$
$= 2 \times 8 – 3 \times 4 + 4 \times 2 + 7$
$= 16 – 12 + 8 + 7$
$= 19$
Remainder $= 19$
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