Question
Find the remainder when $x^3 + 3x^2 + 3x + 1$ is divided by $x + \pi$
✓
Answer
Let $p(x) = x^3 + 3x^2 + 3x + 1$
$x + \pi = 0$
$\Rightarrow x = -\pi$
$\therefore$ Remainder $= (-\pi)^3 + 3(-\pi)^2 + 3(-\pi) + 1$
$= -\pi ^3 + 3\pi^2 - 3\pi + 1$
$x + \pi = 0$
$\Rightarrow x = -\pi$
$\therefore$ Remainder $= (-\pi)^3 + 3(-\pi)^2 + 3(-\pi) + 1$
$= -\pi ^3 + 3\pi^2 - 3\pi + 1$
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