Question
Find the remainder when $x^3+3 x^3+3 x+1$ is divided by: $x+1$
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Answer
Here, $f(x)=x^3+3 x^2+3 x+1$ By remainder theorem
$x+1=0 \Rightarrow x=-1$ substitute the value of $x$ in $f(x) f(-1)=(-1)^3+3(-1)^2+$
$3(-1)+1=-1+3-3+1=0$
$x+1=0 \Rightarrow x=-1$ substitute the value of $x$ in $f(x) f(-1)=(-1)^3+3(-1)^2+$
$3(-1)+1=-1+3-3+1=0$
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