Question
Find the simplest form of:$\frac{1095}{1168}$
✓
Answer
Prime factorisation of $1095$ and $1168$ is:
$1095 = 3 \times 5 \times 73$
$1168 = 2^4 \times 73$
Therefore, $\frac{1095}{1168}=\frac{3\times\text{5}\times73}{2^4\times73}=\frac{15}{16}$
Thus, simplest form of $\frac{1095}{1168}$ is $\frac{15}{16}.$
$1095 = 3 \times 5 \times 73$
$1168 = 2^4 \times 73$
Therefore, $\frac{1095}{1168}=\frac{3\times\text{5}\times73}{2^4\times73}=\frac{15}{16}$
Thus, simplest form of $\frac{1095}{1168}$ is $\frac{15}{16}.$
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