CBSE BoardEnglish MediumSTD 10MathsReal Numbers2 Marks
Question
Find the simplest form of:$\frac{368}{496}$
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Answer
Prime factorisation of 368 and 496 is:
$368=2^4 \times 23$
$496=2^4 \times 31$
Therefore, $\frac{368}{496}=\frac{2^4\times23}{2^4\times31}=\frac{23}{31}$
Thus, simplest form of $\frac{368}{496}$ is $\frac{23}{31}.$
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