Question
Find the simplest form of:$\frac{368}{496}$
✓
Answer
Prime factorisation of $368$ and $496$ is:
$368 = 2^4 \times 23$
$496 = 2^4 \times 31$
Therefore, $\frac{368}{496}=\frac{2^4\times23}{2^4\times31}=\frac{23}{31}$
Thus, simplest form of $\frac{368}{496}$ is $\frac{23}{31}.$
$368 = 2^4 \times 23$
$496 = 2^4 \times 31$
Therefore, $\frac{368}{496}=\frac{2^4\times23}{2^4\times31}=\frac{23}{31}$
Thus, simplest form of $\frac{368}{496}$ is $\frac{23}{31}.$
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