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Real Numbers — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsReal Numbers1 Mark
Question
Find the simplest form of:$\frac{473}{645}$
✓

Answer

Prime factorisation of 473 and 645 is:
473 = 11 × 43
645 = 3 × 5 × 43
Therefore, $\frac{473}{645}=\frac{11\times\text{43}}{3\times5\times43}=\frac{11}{15}$
Thus, simplest form of $\frac{473}{645}$ is $\frac{11}{15}.$

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