Question
Find the slope of the line whose inclination is 30°.
$\therefore$ Slope of the line $=\tan \theta=\tan 30^{\circ}=\frac{1}{\sqrt{3}}$
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where $\mathrm{i}=\sqrt{-1}$, prove that $\mathrm{A}^{\top}=-\mathrm{A}$.
