Question
Find the solution of $\frac{1}{x}-\frac{3}{x}=\frac{5}{2 x}-3$.

Answer

We have, $\frac{1}{x}-\frac{3}{x}=\frac{5}{2 x}-3$
$\Rightarrow \quad \frac{1-3}{x}-\frac{5}{2 x}=-3 \quad$ [transposing $\frac{5}{2 x}$ to LHS]
$\Rightarrow \quad \frac{-2}{x}-\frac{5}{2 x}=-3 \Rightarrow \frac{-4-5}{2 x}=-3$
$\Rightarrow \quad \frac{-9}{2 x}=-3 \Rightarrow \frac{2 x}{-9}=\frac{-1}{3}$
$\Rightarrow \quad x=\frac{-9}{2} \times\left(\frac{-1}{3}\right)\quad$ [multiplying both sides by $\frac{-9}{2}$ ]
$\Rightarrow \quad x=\frac{3}{2}$

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