Question
Find the square root of:
$38\frac{11}{25}$
$38\frac{11}{25}$
✓
Answer
We know,
$\sqrt{38\frac{11}{25}}=\sqrt{\frac{961}{25}}=\frac{\sqrt{961}}{\sqrt{25}}$
Now, let us compute the square roots of the numerator and the denominator separately.
$\sqrt{961}=31$
$\sqrt{25}=5$
$\therefore\sqrt{38\frac{11}{25}}=\frac{31}{5}$
$\sqrt{38\frac{11}{25}}=\sqrt{\frac{961}{25}}=\frac{\sqrt{961}}{\sqrt{25}}$
Now, let us compute the square roots of the numerator and the denominator separately.
$\sqrt{961}=31$
$\sqrt{25}=5$
$\therefore\sqrt{38\frac{11}{25}}=\frac{31}{5}$
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