Question
Find the square root of the following complex numbers: $-5+12\text{i}$

Answer

Let $\text{z}=-5+12\text{i}$ $\Rightarrow|\text{z}|=\sqrt{(-5)^2+12^2}$ $=\sqrt{25+144}$ $=\sqrt{169}$ $=13$ $\therefore\sqrt{-5+12\text{i}}=\pm\Bigg\{\sqrt{\frac{13+(-5)}{2}}+\text{i}\sqrt{\frac{13-(-5)}{2}}\Bigg\} \ (\because\text{y}>0)$ $=\pm\Bigg\{\sqrt{\frac{8}{2}}+\text{i}\sqrt{\frac{18}{2}}\Bigg\}$ $\pm\{2+3\text{i}\}$

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