Question
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication,
$96$

Answer

$(96)^2$
Here $a=9, b=6$
$\text{a}^2$ $\text{2ab}$ $\text{b}^2$
$\ \ \ \ \ (9)^2\\ \ =81\\+\ \ {11}$ $2\times9\times6\\=108\\ \ +3$ $\ \ \ (6)^2\\=36$
$92$ $111$  
$(96)^2=96 \times 96=9216$
$\therefore(96)^2=9216$

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