MCQ
Find the sum 12+22+32+……………+102.
- A325
- B365
- C385
- D435
Solution:
We know, sum of cubes of first n terms is given by
$\Big(\frac{\text{n}(\text{n}+1)}{2}\Big)^2.$
$\text{Here},\text{n}=8. \text{ so },\text{sum}=\Big(\frac{8\times9}{2}\Big)^2=1296.$
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