MCQ
Find the sum 13+23+33+……………+83.
- A1225
- B1184
- C1475
- D1296
Solution:
We know, sum of cubes of first n terms is given by
$\Big(\frac{\text{n}(\text{n}+1)}{2}\Big)^2.$
$\text{Here},\text{n}=8\text{ so},\text{sum}=\Big(\frac{8\times9}{2}\Big)^2+1296.$
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Which of the following is correct for any two complex numbers z1 and z2?
$|\text{z}_1\text{z}_2|=|\text{z}_1||\text{z}_2|$
$\arg(\text{z}_1\text{z}_2)=\arg(\text{z}_1)\cdot\arg(\text{z}_2)$
$|\text{z}_1+\text{z}_2|=|\text{z}_1|+|\text{z}_2|$
$|\text{z}_1+\text{z}_2|\geq|\text{z}_1|-|\text{z}_2|$
If the sum of n terms of an A.P. is given by
Sn = 3n + 2n2, then the common difference of the A.P. is:
The number of ways in which a team of eleven players can be selected from 22 players always including 2 of them and excluding 4 of them is.