MCQ
Find the sum $1^3+2^3+3^3+………+8^3$.
  • A
    $1225$
  • B
    $1184$
  • C
    $1475$
  • $1296$

Answer

Correct option: D.
$1296$
We know, sum of cubes of first $n$ terms is given by $\Big(\frac{\text{n}(\text{n}+1)}{2}\Big)^2.$
$\text{Here},\text{n}=8$
$\text{ so},\text{sum}=\Big(\frac{8\times9}{2}\Big)^2=1296.$

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