Question
Find the sum $-2 \frac{1}{3}+4 \frac{3}{5}$
✓
Answer
As the denominators are different find the $LCM$ of $3 \& 5$
$-2 \frac{1}{3}+4 \frac{3}{5}=-\frac{7}{3}+\frac{23}{5}$
$LCM$ of $3$ and $5$ is $15$
$-7\over 3$ = $- 7\times5\over 3\times 5$ = $-35\over 15$
$23\over 5 $ = $23\times 3\over 5\times3$ = $69\over 15$
Thus, $\frac{-7}{3}+\frac{23}{5}=\frac{-35}{15}+\frac{69}{15}$
$= \frac{-35+69}{15}=\frac{34}{15}=2 \frac{4}{15}$
$-2 \frac{1}{3}+4 \frac{3}{5}=-\frac{7}{3}+\frac{23}{5}$
$LCM$ of $3$ and $5$ is $15$
$-7\over 3$ = $- 7\times5\over 3\times 5$ = $-35\over 15$
$23\over 5 $ = $23\times 3\over 5\times3$ = $69\over 15$
Thus, $\frac{-7}{3}+\frac{23}{5}=\frac{-35}{15}+\frac{69}{15}$
$= \frac{-35+69}{15}=\frac{34}{15}=2 \frac{4}{15}$
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