Question
Find the sum: $2\frac{7}{10}+3\frac{8}{15}$

Answer

We have, $L.C.M$. of $10$ and $15 = (2 \times 3 \times 5) = 30$
$\begin{array}{c|c}5&10,15\\\hline2&2,3\\\hline3&1,3\\\hline&1,1\end{array} $
Therefore, $2\frac{7}{10}+3\frac{8}{15}$
$=\frac{27}{10}+\frac{53}{15}$
$=\frac{(81+106)}{30}$
$\Big(\frac{30}{10}=3,3\times27=81\Big)$ and
$\Big(\frac{30}{15}=2,2\times53=106\Big)$
$=\frac{187}{30}$
$=6\frac{7}{30}$

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