Question
Find the sum:
$4\frac{3}{4}+9\frac{2}{5}$
$4\frac{3}{4}+9\frac{2}{5}$
✓
Answer
We have,
$4\frac{3}{4}+9\frac{2}{5}$
$=\frac{19}{4}+\frac{47}{5}$
Taking out the LCM of 4 and 5, we get
4 × 5 = 20
Now, we convert the given fractions to equivalent fractions by making the denominators 20
$=\frac{19\times5}{4\times5}+\frac{47\times4}{5\times4}$
$=\frac{95}{20}+\frac{188}{20}$
$=\frac{95+188}{20}$
$=\frac{283}{20}$
$4\frac{3}{4}+9\frac{2}{5}$
$=\frac{19}{4}+\frac{47}{5}$
Taking out the LCM of 4 and 5, we get
4 × 5 = 20
Now, we convert the given fractions to equivalent fractions by making the denominators 20
$=\frac{19\times5}{4\times5}+\frac{47\times4}{5\times4}$
$=\frac{95}{20}+\frac{188}{20}$
$=\frac{95+188}{20}$
$=\frac{283}{20}$
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