Question
Find the sum:
$\frac{4}{9}+\frac{8}{9}$
$\frac{4}{9}+\frac{8}{9}$
✓
Answer
The given fractions are like fractions
We know,
Sum of like fractions $=\frac{\text{Sum of the numerators}}{\text{Common denominator}}$
Thus, we have
$\frac{4}{9}+\frac{8}{9}$
$=\frac{(4+8)}{9}$
$=\frac{12}{9}$
$=\frac{4}{3}$
$=1\frac{1}{3}$
We know,
Sum of like fractions $=\frac{\text{Sum of the numerators}}{\text{Common denominator}}$
Thus, we have
$\frac{4}{9}+\frac{8}{9}$
$=\frac{(4+8)}{9}$
$=\frac{12}{9}$
$=\frac{4}{3}$
$=1\frac{1}{3}$
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