Question
Find the sum: $\frac{5}{6}+3+\frac{3}{4}$
✓
Answer
We have, $\frac{5}{6}+3+\frac{3}{4}$
Taking out the $LCM$ of $6$ and $4$, we get $2 \times 2 \times 3 = 12$
Now, we convert the given fractions to equivalent fractions by making the denominators $12$ $=\frac{5\times2}{6\times2}+\frac{3\times12}{12}+\frac{3\times3}{4\times3}$
$=\frac{10}{12}+\frac{36}{12}+\frac{9}{12}$
$=\frac{10+36+9}{12}$
$=\frac{55}{12}$
Taking out the $LCM$ of $6$ and $4$, we get $2 \times 2 \times 3 = 12$
Now, we convert the given fractions to equivalent fractions by making the denominators $12$ $=\frac{5\times2}{6\times2}+\frac{3\times12}{12}+\frac{3\times3}{4\times3}$
$=\frac{10}{12}+\frac{36}{12}+\frac{9}{12}$
$=\frac{10+36+9}{12}$
$=\frac{55}{12}$
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