Question
Find the sum:
$\frac{5}{6}+3+\frac{3}{4}$

Answer

We have,
$\frac{5}{6}+3+\frac{3}{4}$
Taking out the LCM of 6 and 4, we get
2 × 2 × 3 = 12
Now, we convert the given fractions to equivalent fractions by making the denominators 12
$=\frac{5\times2}{6\times2}+\frac{3\times12}{12}+\frac{3\times3}{4\times3}$
$=\frac{10}{12}+\frac{36}{12}+\frac{9}{12}$
$=\frac{10+36+9}{12}$
$=\frac{55}{12}$

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