Question
Find the sum:
$\frac{5}{6}+\frac{7}{8}$
$\frac{5}{6}+\frac{7}{8}$
✓
Answer
$\frac{5}{6}+\frac{7}{8}$
LCM of 6, and 8 = 24
$\therefore\frac{5}{6}=\frac{5\times4}{6\times4}=\frac{20}{24}$
$\frac{7}{8}=\frac{7\times3}{8\times3}=\frac{21}{24}$
$\therefore\frac{5}{6}+\frac{7}{8}=\frac{20}{24}=\frac{21}{24}$
$=\frac{20+21}{24}=\frac{41}{24}=1\frac{17}{24}$
LCM of 6, and 8 = 24
$\therefore\frac{5}{6}=\frac{5\times4}{6\times4}=\frac{20}{24}$
$\frac{7}{8}=\frac{7\times3}{8\times3}=\frac{21}{24}$
$\therefore\frac{5}{6}+\frac{7}{8}=\frac{20}{24}=\frac{21}{24}$
$=\frac{20+21}{24}=\frac{41}{24}=1\frac{17}{24}$
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