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Arithmetic Progression — Maths STD 10 — Question

Maharashtra BoardEnglish MediumSTD 10MathsArithmetic Progression5 Marks
Question
Find the sum of first forty positive intergers divisible by 6.
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Answer

First forty positive intergers divisible by 6 are as follows:
6, 12, 18, 24, ....240
$\therefore\text{S}_{40}=\frac{40}{2}\big[6+240\big]$
$=20\times246$
$=4920$

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