MCQ
 Find the sum of first n terms.
  • A
    $\frac{\text{n}(\text{n}+1)}{2}$
  • B
    $\Big(\frac{\text{n}(\text{n}+1)}{2}\Big)$
  • C
    $\frac{\text{n}(\text{n}+1)(2\text{n}+1)}{6}$
  • D
    $\Big(\frac{\text{n}(\text{n}+1)}{2}\Big)$

Answer

  1. $\frac{\text{n}(\text{n}+1)}{2}$

solution:

Sum of first n terms = 1+2+3+4+……+n

$\Rightarrow\Big(\frac{\text{n}}{2}\Big)=\text{(a}+\text{b)}=\Big(\frac{\text{n}}{2}\Big)(\text{1}+\text{n})=\frac{\text{n}(\text{n}+1)}{2}.$

 

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