Gujarat BoardEnglish MediumSTD 11 ScienceMATHSArithmetic Progressions3 Marks
Question
Find the sum of odd integers from 1 to 2001.
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Answer
Let the number of terms is n. Now the sum of the series is: 1 + 3 + 5 + ... + 2001 Here, $\text{l}=2001$ and $\text{d}=2$ Therefore, $\text{l}=\text{a}+(\text{n}-1)\text{d}$ $2001=1+(\text{n}-1)\text{d}$ $2(\text{n}-1)=2000$ $\text{n}-1=1000$ $\text{n}=1001$ Therefore the sum of the series is: $\text{s}=\frac{1001}{2}[2+(1001-1)2]$ $=1001^2$ $=10021001$
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