Question
Find the sum of the following arithmetic progression:
50, 46, 42, ... to 10 terms.

Answer

50, 46, 42, ... to 10 terms $\text{s}_\text{n}=\frac{\text{n}}{2}[2\text{a}+(\text{n}-1)\text{d}]$ $\text{s}=\frac{10}{2}[2\times50+(10-1)(-4)]$ $=320$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free