Question
Find the sum of the series: 3 + 5 + 7 + 6 + 9 + 12 + 9 + 13 + 17 + ... to 3n terms.

Answer

In the given series 3 + 5 + 7 + 9 + ... to 3n Here, a = 3 d = 2 Number of terms = 3n The sum of n terms is $\text{s}_\text{n}=\frac{\text{n}}{2}[2\text{n}+(\text{n}-1)\text{d}]$ $\text{s}_{3\text{n}}=\frac{3\text{n}}{2}[6+(3\text{n}-1)2]$ $=3\text{n}(2\text{n}+3)$

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