Question
Find the surface area of a cube whosevolume is:
$216\ dm^3$

Answer

Volume of cube $= 216\ dm^3$
$\therefore$ Edge $(a) = \sqrt[3]{216}\text{dm}$
$=\sqrt[3]{6\times6\times6}=\sqrt[3]{6^3}\text{dm}=6\text{dm}$
$\therefore$ Surface area $= 6a^2= 6(6)^2dm^2$
$= 6 × 36 = 216\ dm^2$

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