Question
Find the surface area of a cube whose volume is:
$343m^3$

Answer

Volume of a cube $= 343m^3$
 $\therefore$ Edge (a) $=\sqrt[3]{\text{Volume}}=\sqrt[3]{323}$
$=\sqrt[3]{7\times7\times7}=\sqrt[3]{7^3}=7\text{m}$
$\therefore$ Surface area $= 6a^2= 6(7)^2m^2$
$= 6 × 49 = 294m^2$

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