Question
Find the surface area of a cube whose volume is:
$343 m^3$

Answer

Volume of a cube $=343 m^3$
$\therefore$ Edge (a) $=\sqrt[3]{\text{Volume}}=\sqrt[3]{323}$
$=\sqrt[3]{7\times7\times7}=\sqrt[3]{7^3}=7\text{m}$
$\therefore \text { Surface area }=6 a^2=6(7)^2 m^2$
$=6 \times 49=294 m^2$

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