Question
Find the surface area of a sphere whose volume is $606.375m^3.$ $\big(\text{Take}\ \pi=\frac{22}{7}\big).$
✓
Answer
Volume of the sphere $= 606.375m^3$
Then, $\frac{4}{3}\pi\text{r}^3=606.375$
$\Rightarrow\text{r}^3=\frac{606.375\times3\times7}{4\times22}=144.703$
$\Rightarrow\text{r}=5.25\text{m}$
$\therefore$ Surface area $=4\pi\text{r}^2$
$=4\times\frac{22}{7}\times5.25\times5.25$
$=346.5\text{m}^2$
Then, $\frac{4}{3}\pi\text{r}^3=606.375$
$\Rightarrow\text{r}^3=\frac{606.375\times3\times7}{4\times22}=144.703$
$\Rightarrow\text{r}=5.25\text{m}$
$\therefore$ Surface area $=4\pi\text{r}^2$
$=4\times\frac{22}{7}\times5.25\times5.25$
$=346.5\text{m}^2$
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