Question
Find the fraction equivalent of $\frac{35}{42}$, having:Numerator $15$
✓
Answer
Firstly, we will reduce $\frac{35}{42}$ into the lowest term.
Now, we will divide both the numerator & denominator by the $HCFs$ of $35\ \&\ 42.$
$\Rightarrow\frac{35\div7}{42\div7}=\frac{5}{6}$
$\frac{5}{6}=\frac{15}{}$
Consider the numerator $= 15$
As $5 \times 3 = 15,$
we will multiply both the numerator & denominator by $3.$
$\Rightarrow\frac{5\ \times\ 3}{6\ \times\ 3}=\frac{15}{18}$
Now, we will divide both the numerator & denominator by the $HCFs$ of $35\ \&\ 42.$
$\Rightarrow\frac{35\div7}{42\div7}=\frac{5}{6}$
$\frac{5}{6}=\frac{15}{}$
Consider the numerator $= 15$
As $5 \times 3 = 15,$
we will multiply both the numerator & denominator by $3.$
$\Rightarrow\frac{5\ \times\ 3}{6\ \times\ 3}=\frac{15}{18}$
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