Question
Find the fraction equivalent of $\frac{35}{42}$, having:Numerator 15

Answer

Firstly, we will reduce $\frac{35}{42}$ into the lowest term.
Now, we will divide both the numerator & denominator by the HCFs of 35 & 42.
$\Rightarrow\frac{35\div7}{42\div7}=\frac{5}{6}$
$\frac{5}{6}=\frac{15}{}$
Consider the numerator $= 15$
As 5 × 3 = 15, we will multiply both the numerator & denominator by 3.
$\Rightarrow\frac{5\ \times\ 3}{6\ \times\ 3}=\frac{15}{18}$

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