Question
Find the trigonometric functions of $: – 90^\circ$
✓
Answer
Angle of measure $\left(-90^{\circ}\right)$ :
Let $m \angle X O A=-90^{\circ}$
It terminal arm (ray $O A$ ) intersects the standard unit circle at $P(0,-1)$
$ \therefore x=0 \text { and } y=-1$
$\sin \left(-90^{\circ}\right)=y=-1$
$\cos \left(-90^{\circ}\right)=s=0$
$\tan \left(-90^{\circ}\right)=\frac{y}{x}$
$=\frac{-1}{0},$
which is not defined.
$\operatorname{cosec}\left(-90^{\circ}\right)=\frac{1}{y}$
$=\frac{1}{-1}=-1$
$\sec \left(-90^{\circ}\right)=\frac{1}{x}=\frac{1}{0}$
which is not defined.
$\cot \left(-90^{\circ}\right)=\frac{x}{y}=\frac{0}{-1}=0$
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