Question
Find the vallue of $n$ when:
$8 \times 2^{n+2}=32$
$8 \times 2^{n+2}=32$
✓
Answer
$8 \times 2^{n+2}=32$
$2^{n+2}=\frac{32}{8}$
$4=2^2$
Comparing we get,
$\mathrm{n}+2=2$
$\Rightarrow \mathrm{n}=2-2=0$
$\therefore \mathrm{n}=0$
$2^{n+2}=\frac{32}{8}$
$4=2^2$
Comparing we get,
$\mathrm{n}+2=2$
$\Rightarrow \mathrm{n}=2-2=0$
$\therefore \mathrm{n}=0$
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