Find the vallue of n when: 8 2^ n+2 =32 - Vidyadip

Question

Find the vallue of n when:
$8 \times 2^{n+2}=32$

✓

Answer

$8 \times 2^{ n +2}=32$
$2^{n+2}=\frac{32}{8}$
$4=2^2$
Comparing we get,
$n+2=2$
$\Rightarrow n=2-2=0$
$\therefore n=0$

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