Question
Find the value of: ${ }^{20} \mathrm{C}_{16}-{ }^{19} \mathrm{C}_{16}$

Answer

$
\begin{aligned}
{ }^{20} \mathrm{C}_{16}-{ }^{19} \mathrm{C}_{16} & =\frac{20 !}{16 ! 4 !}-\frac{19 !}{16 ! 3 !} \\
& =\frac{20 \times 19 !}{16 ! \times 4 \times 3 !}-\frac{19 !}{16 ! 3 !} \\
& =\frac{19 !}{3 ! 16 !}\left[\frac{20}{4}-1\right] \\
& =\frac{19 !}{3 ! 16 !}(4) \\
& =\frac{19 !}{3 !(16)(15 !)} 4 \\
& =\frac{19 !}{4(3 !)(15 !)} \\
& =\frac{19 !}{4 ! 15 !} \\
& ={ }^{19} \mathrm{C}_{15} \text { or }{ }^{19} \mathrm{C}_4=3876
\end{aligned}
$

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