Question
Find the value of:
$(-3)+(-8)\div(-4)-2\times(-2)$
$(-3)+(-8)\div(-4)-2\times(-2)$
✓
Answer
$(-3)+(-8)\div(-4)-2\times(-2)$
$=(-3)+\frac{(-8)}{(-4)}-2\times(-2)$
$=-3+2+4$
$=6-3$
$=3$
$=(-3)+\frac{(-8)}{(-4)}-2\times(-2)$
$=-3+2+4$
$=6-3$
$=3$
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