Question
Find the value of $\frac{3}{13} \div\left(\frac{-4}{65}\right)$

Answer

$\frac{3}{13} \div\left(\frac{-4}{65}\right)=\frac{3}{13} \times\left(\frac{65}{-4}\right)$
As $13$ times $5$ equals to $65[13 \times 5 = 65]$
$\frac{3 \times 5}{1 \times-4}=\frac{-15}{4}=-3 \frac{3}{4}$

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