Question
Find the value of:
$\left(8^0-2^0\right) \times\left(8^0+2^0\right)$
$\left(8^0-2^0\right) \times\left(8^0+2^0\right)$
✓
Answer
$\left(8^0-2^0\right) \times\left(8^0+2^0\right)$
$=(1-1) \times(1+1)$
${\left[\because a^0=1\right]}$
$=0 \times 2=0$
$=(1-1) \times(1+1)$
${\left[\because a^0=1\right]}$
$=0 \times 2=0$
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