Question
Find the value of:
$\big(2^{-1}\times3^{-1}\big)\div2^{-3}$
$\big(2^{-1}\times3^{-1}\big)\div2^{-3}$
✓
Answer
$\big(2^{-1}\times3^{-1}\big)\div2^{-3}$$=\Big(\frac{1}{2}\times\frac{1}{3}\Big)\div\frac{1}{2^3}$
$=\frac{1}{6}\div\frac{1}{8}$
$=\frac{1}{6}\times\frac{8}{1}$
$=\frac{4}{3}$
$=\frac{1}{6}\div\frac{1}{8}$
$=\frac{1}{6}\times\frac{8}{1}$
$=\frac{4}{3}$
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