Question
Find the value of discriminant.
2y2 – 5y + 10 = 0

Answer


$\begin{array}{l}2 y^2-5 y+10=0 \text { compare with } a x^2+b x+c=0 \\ \Rightarrow a=2, b=-5 \text { and } c=10 \\ \therefore b^2-4 a c=-5^2-4(2)(10) \\ =25-80 \\ =-55\end{array}$

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