Question
Find the value of expression $2 sec ^{-1} 2+\sin ^{-1}\left(\frac{1}{2}\right)$

Answer

$2 \sec ^{-1}(2)+\sin ^{-1}\left(\frac{1}{2}\right)$
$=2 \times \frac{\pi}{3}+\frac{\pi}{6}$
$=\frac{2 \pi}{3}+\frac{\pi}{6}$
$=\frac{5 \pi}{6} \text { }$

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