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Permutations and Combinations (p-2) — Maths (commerce) STD 11 Commerce / Arts — Question

Maharashtra BoardEnglish MediumSTD 11 Commerce / ArtsMaths (commerce)Permutations and Combinations (p-2)1 Mark
Question
Find the value of: $\frac{5(26 !)+(27 !)}{4(27 !)-8(26 !)}$
✓

Answer

$
\begin{aligned}
\frac{5(26 !)+27 !}{4(27 !)-8(26 !)} & =\frac{5(26 !)+27(26 !)}{4(27 \times 26 !)-8(26 !)} \\
& =\frac{26 !(5+27)}{4(26 !)(27-2)} \\
& =\frac{32}{(4)(25)}=\frac{8}{25}
\end{aligned}
$

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