Question
Find the value of $\frac{\cos 56^{\circ}}{\sin 34^{\circ}}$

Answer

$56^{\circ}+34^{\circ}=90^{\circ}$ means 56 and 34 are the measures of complimentary angles.
$
\begin{aligned}
\sin \theta & =\cos (90-\theta) \\
\therefore \quad \sin 34^{\circ} & =\cos (90-34)^{\circ}=\cos 56^{\circ} \\
\therefore \quad & \frac{\cos 56^{\circ}}{\sin 34^{\circ}}=\frac{\cos 56^{\circ}}{\cos 56^{\circ}}=1
\end{aligned}
$

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