Question
Find the value of $\int_0^\pi \frac{\sec x}{\sec x+\tan x} d x$.
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f(x) = 16x2 - 16x + 28 on R.
$(1+\text{x})(1+\text{y}^2)\text{dx}+(1+\text{y})(1+\text{x}^2)\text{dy}=0$