Question
Find the value of $k$ for which the function.
$
f(x)=\left\{\begin{array}{cc}
\frac{x^2+3 x-10}{x-2}, & x \neq 2 \\
k, & x=2
\end{array}\right.
$
is continuous at $x=2$.

Answer

$\lim _{x \rightarrow 2} f(x)=f(2)=k$
$\lim _{x \rightarrow 2} \frac{(x+5)(x-2)}{x-2}=k \quad(x \neq 2)$
$\therefore \quad k=7$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free