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MATRICES — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsMATRICES2 Marks
Question
Find the value of $\lambda,$ non-zero scalar, if $\lambda\begin{bmatrix}1&0&2\\3&4&5\end{bmatrix}+2\begin{bmatrix}1&2&3\\-1&-3&2\end{bmatrix}=\begin{bmatrix}4&4&10\\4&2&14\end{bmatrix}$
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Answer

Given: $\lambda\begin{bmatrix}1&0&2\\3&4&5\end{bmatrix}+2\begin{bmatrix}1&2&3\\-1&-3&2\end{bmatrix}=\begin{bmatrix}4&4&10\\4&2&14\end{bmatrix}$
$\Rightarrow\begin{bmatrix}\lambda&0&2\lambda\\3\lambda&4\lambda&5\lambda\end{bmatrix}+\begin{bmatrix}2&4&6\\-2&-6&4\end{bmatrix}=\begin{bmatrix}4&4&10\\4&2&14\end{bmatrix}$
$\Rightarrow\begin{bmatrix}\lambda+2&0+4&2\lambda+6\\3\lambda-2&4\lambda-6&5\lambda+4\end{bmatrix}=\begin{bmatrix}4&4&10\\4&2&14\end{bmatrix}$
$\Rightarrow\lambda+2=4$
$\Rightarrow\lambda=4-2$
$\therefore\ \lambda=2$

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