Find the value of (-19 3 ). - Vidyadip

MCQ

Find the value of $\sec \left(\frac{-19 \pi}{3}\right)$.

A
$\frac{1}{2}$
B
-2
C
2
D
$\frac{-1}{2}$

✓

Answer

(c) 2
Explanation: $\sec \left(\frac{-19 \pi}{3}\right)=\sec \frac{19 \pi}{3}[\because \sec (-\theta)=\sec \theta]$
$=\sec \left(6 \pi+\frac{\pi}{3}\right)=\sec \frac{\pi}{3}=2[\because \sec (2 n \pi+\theta)=\sec \theta]$

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